How do you find three consecutive integers whose sum is 42? | Socratic (2024)

If we represent the smallest of the three consecutive integers as #x# then the other two integers are #(x+1)# and #(x+2)#

We are told
#(x) + (x+1) + (x+2) = 42#

#rarr 3x+3 = 42#

#rarr 3x = 39#

#rarr x = 13#

and the three consecutive integers are 13, 14, and 15.

See Also
Using the identity and proof: x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx).
See Also
Sum of Cubes Formula - Examples | a^3 + b^3 Formulaa + b + c Whole Cube: Identity, Formula with Solved ExamplesThe answer to life, the universe, and everythingWhat is 3 to the 4th power? [Solved]
How do you find three consecutive integers whose sum is 42? | Socratic (2024)
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